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Hash Code reveals Lost TV Series ending?
"A post on the respected fansite Dark UFO has claimed that the show's conclusion will become apparent to whoever decrypts the code:
"626110432547f398491fad32d6add11b
-- "Cult News: Hash code reveals 'Lost' ending?", digitalspy.co.uk, Saturday, February 6 2010
They will add a video on the
Submitted by Torrija (not verified) on Fri, 02/19/2010 - 08:53.They will add a video on the internet with the solution. It's MD5 will be that one.
Maybe there is something more..
Submitted by lancedehm (not verified) on Thu, 02/11/2010 - 18:05.First looking at the text appear to be a valid MD5(128 bit, 32chars) checksum hash, no dictionary reverse-know by a rainbow table (read below) that's looks more complicated.
If really is a md5 checksum hash <maybe> it's was created by adding "salt" to the original message, for example: md5(hello) = hash1 & md5(hello.salt) = hash2 -> hash1 != hash2, so collisionning the main md5 without a clue is only crap and the amount of time to do it is exponencially stupid!
Nothing more to say!
C'ya
Played with the numbers and letter.
Submitted by Paul T (not verified) on Wed, 02/10/2010 - 20:08.ff ada ddd b
aa ff ddd b
aa ddd ff b
b a a f f d d d
2+11+44+66 = 123
51
36
34
33
29
32
18
17
15
10
10 51 32 33 34 15 36 17 18 29
1 5 3 3 3 1 3 1 1 2
12 15 41 43
2 5 1 3 - 1 2 3 (123 from above)
5 = www.five.com
Decode time
Submitted by Anonymous (not verified) on Wed, 02/10/2010 - 02:13.My computer can do arond 300 000 000 combinations per second (just for alphanumeric + space). The estimated time to decode is 6760 days 1 hour and 48 minutes. If we had access to a distributed farm of few thousands machines we could crack it.
Heureka! Partly...
Submitted by Jan (not verified) on Tue, 02/09/2010 - 15:49.Maybe I found it. I typed this code to DEC/CHAR on
http://home2.paulschou.net/tools/xlate/
and it spitted in BASE64 this code /5sgBgsA
which seems like a part of some shortening web address (like goo.gl)
but http://goo.gl/5sgBgsA does´nt work, I think its another kind of addres, but I can´t find out which.
Hope it is it!
i tried
Submitted by tinyurl (not verified) on Tue, 02/09/2010 - 23:25.i tried http://tinyurl.com/5sgBgsA it is not :(
MD5 hash
Submitted by Ciusbet (not verified) on Mon, 02/08/2010 - 22:24.It's a normal 128bit MD5 hash (hex):
62 61 10 43 25 47 f3 98 49 1f ad 32 d6 ad d1 1b (16 bytes, 128 bit)
It's impossible to crack, because a hash does not save the information about data. It's only possible to calculate a collision with the same hash
It's like a checksum
Submitted by Anon (not verified) on Tue, 02/09/2010 - 00:49.So it's like a checksum, so the original message can not be derived from it. You would have to guess the orginal message (which could be of any length), and then see whether it generates the same MD5 hash. Hence there is no encoded/encrypted message.
Original source?
Submitted by Anon (not verified) on Sun, 02/07/2010 - 17:43.Anyone know where the original source of this story came from? The digitalspy story claims that it came from fansite Dark UFO, but there only seems to be a single references to a Twitter post. Looks like garbage to me.
http://spoilerslost.blogspot.
Submitted by Anonymous (not verified) on Sun, 02/07/2010 - 18:54.http://spoilerslost.blogspot.com/2010/02/cryptic-clue-to-end-of-lost.html
Decoding
Submitted by Anonymous (not verified) on Sun, 02/07/2010 - 17:31."626110432547f398491fad32d6add11b" is only 12 hexadecimal 8-bit characters. We need a minimum of 5 bits per alphabetical characters, so this could represent 12 x 8 / 5 = 19 5-bit characters.
4541aa0ed38bf4dbfa3aa325c80fb329
Submitted by Anonymous (not verified) on Sun, 02/07/2010 - 14:23.4541aa0ed38bf4dbfa3aa325c80fb329
Cryptic
Submitted by Anonymous too (not verified) on Sun, 02/07/2010 - 15:00.A little cryptic, but "4541aa0ed38bf4dbfa3aa325c80fb329"appears to be the MD5 of "626110432547f398491fad32d6add11b"
626110432547f398491fad32d6add11b
Submitted by Chris (not verified) on Sun, 02/07/2010 - 12:48.Decoded this means - "it ends where it began"
What this means is anyones guess. Jack Waking up in the jungle perhaps??
wrong
Submitted by Alexandre de Sá (not verified) on Mon, 02/08/2010 - 05:01.it ends where it began = 0e917939fcc788d8c70ca2725f073e0d
It ends where it began
Submitted by Nigel Smith (not verified) on Sun, 02/07/2010 - 13:00."it ends where it began"
Is this a guess, or how did you work it out?
Just ran the encryption, I
Submitted by Chris (not verified) on Sun, 02/07/2010 - 23:39.Just ran the encryption, I hope this aint legit though because this ending should suck.
Really?
Submitted by Anonymous (not verified) on Mon, 02/08/2010 - 20:49.What do you mean you "just ran the encryption"? That statement makes no sense. If this is in fact an MD5 checksum then what you should have done first would have been to attempt to reverse it. If you had you would have received: 4541aa0ed38bf4dbfa3aa325c80fb329
Which makes absolutely no sense correct?
The next step would be to run Cain or some other script kiddie tool against the hash with a dictionary file. If my hunch is correct it would likely be written in Latin (the language of the "others" and the island) therefore rendering and dictionary file completely useless unless you know someone who has the ability to create a Latin dictionary file. I'm gonna go ahead and guess the answer is no on that one.
The only other step you could have taken after this would have been a brute force attack on the checksum. The response you posted is 21 characters long (including spaces) which is pretty darn big. Now i'm no rocket scientist but you have one heck of a super computer on your hands if you cracked that large of an MD5 in less than 24 hours.... Maybe if you weren't so stingy with it we could have allowed the SETI people to have worked out a time share deal with the good folks on Jupiter by now and all be frolicking around on one of their moons for vacation....
What I'm getting at is there is no way you came to that conclusion in any manner other than rectal excretion. If you have opinions keep them to yourself. If you have facts share them.
Lostpedia discussion
Submitted by Johnny J. (not verified) on Sun, 02/07/2010 - 11:56.lostpedia.com has a discussion where someone suggests that it translates into:
"6 numbers lost, 6 billion saved."
That doesn't seem like a solution to me.
yes it does fool, oceanic 6
Submitted by Anonymous (not verified) on Mon, 02/08/2010 - 21:28.yes it does fool,
oceanic 6 died , to save the world
Other 6 numbers possibility
Submitted by Chris (not verified) on Mon, 02/08/2010 - 23:09.It is possible 6 numbers also refers to the actual numbers: 4, 8, 15, 16, 23, 42
this was my thought when i
Submitted by Anonymous (not verified) on Tue, 02/09/2010 - 04:17.this was my thought when i read "6 numbers"!!
No solution
Submitted by Nigel Smith (not verified) on Sun, 02/07/2010 - 00:33.The "MD5 conversion and MD5 reverse lookup" results in no valid string. Looks like it could be a hoax.
MD5? Good luck...
Submitted by The Wall (not verified) on Mon, 02/08/2010 - 16:42.Not even NASA has been able to decrypt MD5. So if the ending is hiding there and it's encrypted in MD5 you will have to wait until may to know the ending.
How do you know it's MD5?
Submitted by Mad mad (not verified) on Sun, 02/07/2010 - 12:01.What makes the code MD5? Couldn't just as easily be a simply hex substitution?
I wrote a quick PHP script to
Submitted by Kate6 (not verified) on Sat, 02/13/2010 - 10:50.I wrote a quick PHP script to try to interpret it as a hex representation of an ASCII string. As it turns out, more than half the characters aren't even in the printable character range (32 decimal to 128 decimal). But this is what it comes out to:
hex=>dec=>ASCII (NP = nonprintable)
0x62=> 98=>b
0x61=> 97=>a
0x10=> 16=>[NP]
0x43=> 67=>C
0x25=> 37=>%
0x47=> 71=>G
0xf3=>243=>[NP]
0x98=>152=>[NP]
0x49=> 73=>I
0x1f=> 31=>[NP]
0xad=>173=>[NP]
0x32=> 50=>2
0xd6=>214=>[NP]
0xad=>173=>[NP]
0xd1=>209=>[NP]
0x1b=> 27=>[NP]
"ba[NP]C%G[NP][NP]I[NP][NP]2[NP][NP][NP][NP]"